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# Op֐̕Ɋւ

(1).̕DC$3\displaystyle{0\leq {\theta}< 2{\pi}}$ ƂD

 $3\displaystyle{ \sin {\theta}=\frac{\hspace{2}1\hspace{2}}{\hspace{2}2\hspace{2}} }$ $3\displaystyle{\cos {\theta}=\frac{\hspace{2}1\hspace{2}}{\hspace{2}2\hspace{2}}}$ $3\displaystyle{ \sqrt{3}\tan {\theta}=1 }$ $3\displaystyle{ \sin {\theta}=\frac{\hspace{2}1\hspace{2}}{\hspace{2} \sqrt{2} \hspace{2}} }$ $3\displaystyle{ \cos {\theta}=\frac{\hspace{2}1\hspace{2}}{\hspace{2} \sqrt{2} \hspace{2}} }$ $3\displaystyle{\tan {\theta}=1}$ $3\displaystyle{\sin {\theta}=\frac{\hspace{2} \sqrt{3} \hspace{2}}{\hspace{2}2\hspace{2}}}$ $3\displaystyle{\cos {\theta}=\frac{\hspace{2} \sqrt{3} \hspace{2}}{\hspace{2}2\hspace{2}}}$ $3\displaystyle{ \tan {\theta}=\sqrt{3} }$ $3\displaystyle{ \sin {\theta}=1 }$ $3\displaystyle{\cos {\theta}=1}$ $3\displaystyle{\sqrt{3}\tan {\theta}=- 1}$ $3\displaystyle{ \sin {\theta}=0 }$ $3\displaystyle{\cos {\theta}=0}$ $3\displaystyle{\tan {\theta}=- 1}$ $3\displaystyle{\sin {\theta}=- 1}$ $3\displaystyle{\cos {\theta}=- 1}$ $3\displaystyle{\tan {\theta}=- \sqrt{3}}$ $3\displaystyle{\sin {\theta}=- \frac{\hspace{2}1\hspace{2}}{\hspace{2}2\hspace{2}}}$ $3\displaystyle{\cos {\theta}=- \frac{\hspace{2}1\hspace{2}}{\hspace{2}2\hspace{2}}}$ $3\displaystyle{\sin {\theta}=- \frac{\hspace{2}1\hspace{2}}{\hspace{2} \sqrt{2} \hspace{2}}}$ $3\displaystyle{\cos {\theta}=- \frac{\hspace{2}1\hspace{2}}{\hspace{2} \sqrt{2} \hspace{2}}}$ $3\displaystyle{\sin {\theta}=- \frac{\hspace{2} \sqrt{3} \hspace{2}}{\hspace{2}2\hspace{2}}}$ $3\displaystyle{\cos {\theta}=- \frac{\hspace{2} \sqrt{3} \hspace{2}}{\hspace{2}2\hspace{2}}}$

 $3\displaystyle{ 2{ \sin }^{2}{\theta}- \sin {\theta}- 1=0 }$ $3\displaystyle{\sqrt{2}{\cos }^{2}{\theta}- \(\sqrt{2}+1\)\cos {\theta}+1=0}$ $3\displaystyle{- 2{\cos }^{2}{\theta}+\sin {\theta}+1=0}$ $3\displaystyle{- 4{\sin }^{2}{\theta}+1=0}$ $3\displaystyle{2{\cos }^{2}{\theta}{\tan }^{2}{\theta}- 1=0}$ $3\displaystyle{2\sin {\theta}\tan {\theta}=- 3}$ $3\displaystyle{2\sin 2{\theta}=- 1}$ $3\displaystyle{2\cos 3{\theta}=\sqrt{3}}$ $3\displaystyle{2\sin \( {\theta}+\frac{\hspace{2}1\hspace{2}}{\hspace{2}3\hspace{2}}{\pi} \) =1}$ $3\displaystyle{\sqrt{2}\cos \( {\theta}+{\pi} \) =- 1}$ $3\displaystyle{2\sin \( 2{\theta}+\frac{\hspace{2}1\hspace{2}}{\hspace{2}6\hspace{2}}{\pi} \) =- 1}$ $3\displaystyle{2\cos \( 3{\theta}+\frac{\hspace{2}1\hspace{2}}{\hspace{2}2\hspace{2}}{\pi} \) =\sqrt{3}}$

(2)D̍̕őlƍŏl߂D

 $3\displaystyle{y=\sin \({\theta}+\frac{\hspace{2}1\hspace{2}}{\hspace{2}6\hspace{2}}{\pi}\)}$     $3\displaystyle{ \( 0\leq {\theta}\leq \frac{\hspace{2}1\hspace{2}}{\hspace{2}3\hspace{2}}{\pi} \) }$ $3\displaystyle{y=2\cos \hspace{5}\hspace{5}\hspace{5}\hspace{5}\hspace{5}\hspace{5}\hspace{5}\hspace{5}\(2{\theta}+\frac{\hspace{2}2\hspace{2}}{\hspace{2}3\hspace{2}}{\pi}\)}$     $3\displaystyle{\(0\leq {\theta}\leq \frac{\hspace{2}1\hspace{2}}{\hspace{2}3\hspace{2}}{\pi}\)}$

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