三角関数計算の基礎:tanx偏

三角関数計算の基礎 $3$\displaystyle{\tan x}$ 編

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$3$\displaystyle{\tan $ \frac{\hspace{2}{\pi}\hspace{2}}{\hspace{2}2\hspace{2}}+{\theta} $ =- \frac{\hspace{2}1\hspace{2}}{\hspace{2} \tan {\theta} \hspace{2}}}$

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$3$\displaystyle{\tan $ \frac{\hspace{2}{\pi}\hspace{2}}{\hspace{2}2\hspace{2}}+{\theta} $ =- \frac{\hspace{2}1\hspace{2}}{\hspace{2} \tan {\theta} \hspace{2}}}$

三角関数の定義より，

$3$\displaystyle{ \{\begin{array}{lll}\tan {\theta}=\frac{\hspace{2}y\hspace{2}}{\hspace{2}x\hspace{2}}& \vspace{6}\\ \tan $ \frac{\hspace{2}{\pi}\hspace{2}}{\hspace{2}2\hspace{2}}+{\theta} $ =\frac{\hspace{2}x\hspace{2}}{\hspace{2} - y \hspace{2}}& \vspace{6}\\ \end{array} }$

よって，

$3$\displaystyle{\tan $ \frac{\hspace{2}{\pi}\hspace{2}}{\hspace{2}2\hspace{2}}+{\theta} $ =- \frac{\hspace{2}1\hspace{2}}{\hspace{2} \tan {\theta} \hspace{2}}}$

となる。

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