微分(1)の2.(4)解答

$3$\displaystyle{ f $x$ =\sqrt{x} }$
$3$\displaystyle{ \begin{array}{lll} f $x$ &=& {x}^{ \frac{\hspace{2}1\hspace{2}}{\hspace{2}2\hspace{2}} } & \vspace{6}\\ {f}^{\prime } $x$ &=& \frac{\hspace{2}1\hspace{2}}{\hspace{2}2\hspace{2}}{x}^{ \frac{\hspace{2}1\hspace{2}}{\hspace{2}2\hspace{2}}- 1 } & \vspace{6}\\ &=& \frac{\hspace{2}1\hspace{2}}{\hspace{2}2\hspace{2}}{x}^{ \frac{\hspace{2} - 1 \hspace{2}}{\hspace{2}2\hspace{2}} } & \vspace{6}\\ &=& \frac{\hspace{2}1\hspace{2}}{\hspace{2}2\hspace{2}}\cdot \frac{\hspace{2}1\hspace{2}}{\hspace{2} {x}^{ \frac{\hspace{2}1\hspace{2}}{\hspace{2}2\hspace{2}} } \hspace{2}} & \vspace{6}\\ &=& \frac{\hspace{2}1\hspace{2}}{\hspace{2} 2\sqrt{x} \hspace{2}} & \vspace{6}\\ \end{array} }$
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