?A微分	$3$\displaystyle{\frac{\hspace{2}d\hspace{2}}{\hspace{2} dx \hspace{2}}\cot x}$

$3$\displaystyle{\begin{array}{lll}{ $ \cot x $ }^{\prime }& \vspace{6}\\ ={ $ \frac{\hspace{2} \cos x \hspace{2}}{\hspace{2} \sin x \hspace{2}} $ }^{\prime }& \vspace{6}\\ =\frac{\hspace{2} { $ \cos x $ }^{\prime }\sin x- \cos x{ $ \sin x $ }^{\prime } \hspace{2}}{\hspace{2} { $ \sin x $ }^{2} \hspace{2}}& \vspace{6}\\ =\frac{\hspace{2} - { \sin }^{2}x- { \cos }^{2}x \hspace{2}}{\hspace{2} { \sin }^{2}x \hspace{2}}& \vspace{6}\\ =- \frac{\hspace{2}1\hspace{2}}{\hspace{2} { \sin }^{2}x \hspace{2}}& \vspace{6}\\ =- \cos e{c}^{2}x& \vspace{6}\\ \end{array}}$

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