微分(3)の1．(2)の解答

$3$\displaystyle{ y={e}^{ 5x+2 } }$
$3$\displaystyle{\begin{array}u&=& 5x+2 & \vspace{6}\\ \end{array}}$
$3$\displaystyle{\begin{array}y&=& {e}^{u} & \vspace{6}\\ \end{array}}$ とおく。
$3$\displaystyle{\begin{array} \frac{\hspace{2} du \hspace{2}}{\hspace{2} dx \hspace{2}} &=&5& \vspace{6}\\ \end{array}}$ かつ
$3$\displaystyle{\begin{array} \frac{\hspace{2} dy \hspace{2}}{\hspace{2} du \hspace{2}} &=& {e}^{u} & \vspace{6}\\ \end{array}}$ より
$3$\displaystyle{\begin{array}{lll} \frac{\hspace{2} dy \hspace{2}}{\hspace{2} dx \hspace{2}} &=& \frac{\hspace{2} dy \hspace{2}}{\hspace{2} du \hspace{2}}\cdot \frac{\hspace{2} du \hspace{2}}{\hspace{2} dx \hspace{2}} & \vspace{6}\\ &=& 5\cdot {e}^{u} & \vspace{6}\\ &=& 5{e}^{ 5x+2 } & \vspace{6}\\ \end{array}}$
⇒次の問題の解答
⇒ヒント1
⇒微分(3)のTOPへ戻る