積分(3)の1．(5)の解答

$3$\displaystyle{ \int 4{ \cos }^{2}xdx }$
$3$\displaystyle{\begin{array}{lll}=& \int 4\cdot \frac{\hspace{2} 1+\cos 2x \hspace{2}}{\hspace{2}2\hspace{2}}dx & \vspace{6}\\ =& 2\int $ 1+\cos 2x $ dx & \vspace{6}\\ =& 2 $ x+\frac{\hspace{2}1\hspace{2}}{\hspace{2}2\hspace{2}}\sin 2x $ +C & \vspace{6}\\ =& 2x+\sin 2x+C & \vspace{6}\\ \end{array}}$
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