外積の計算則 結合法則は不成立

a→×b→×c→≠a→×b→×c→

a → × b → × c → = a → · c → b → − b → · c → a →

a → × b → × c → = a → · c → b → − a → · b → c →

よって

a → × b → × c → ≠ a → × b → × c →

となり,結合法則は成り立たない.

■説明

a → = a 1 , a 2 , a 3 , b → = b 1 , b 2 , b 3 , c → = c 1 , c 2 , c 3

とおく.

● a → × b → × c →

a → × b → × c → = a 1 , a 2 , a 3 × b 1 , b 2 , b 3 × c 1 , c 2 , c 3

= a 2 b 3 − a 3 b 2 , a 3 b 1 − a 1 b 3 , a 1 b 2 − a 2 b 1 × c 1 , c 2 , c 3

= a 3 b 1 − a 1 b 3 c 3 − a 1 b 2 − a 2 b 1 c 2   , a 1 b 2 − a 2 b 1 c 1 − a 2 b 3 − a 3 b 2 c 3     , a 2 b 3 − a 3 b 2 c 2 − a 3 b 1 − a 1 b 3 c 1

= a 3 b 1 c 3 − a 1 b 3 c 3 − a 1 b 2 c 2 + a 2 b 1 c 2   , a 1 b 2 c 1 − a 2 b 1 c 1 − a 2 b 3 c 3 + a 3 b 2 c 3    , a 2 b 3 c 2 − a 3 b 2 c 2 − a 3 b 1 c 1 + a 1 b 3 c 1

= a 3 b 1 c 3 + a 2 b 1 c 2 − a 1 b 3 c 3 + a 1 b 2 c 2   , a 1 b 2 c 1 + a 3 b 2 c 3 − a 2 b 1 c 1 + a 2 b 3 c 3    , a 2 b 3 c 2 + a 1 b 3 c 1 − a 3 b 2 c 2 + a 3 b 1 c 1

= a 3 c 3 + a 2 c 2 b 1 − b 3 c 3 + b 2 c 2 a 1   , a 1 c 1 + a 3 c 3 b 2 − b 1 c 1 + b 3 c 3 a 2     , a 2 c 2 + a 1 c 1 b 3 − b 2 c 2 + b 1 c 1 a 3

= a 3 c 3 + a 2 c 2 b 1 − b 3 c 3 + b 2 c 2 a 1 + a 1 b 1 c 1 − a 1 b 1 c 1   , a 1 c 1 + a 3 c 3 b 2 − b 1 c 1 + b 3 c 3 a 2 + a 2 b 2 c 2 − a 2 b 2 c 2     , a 2 c 2 + a 1 c 1 b 3 − b 2 c 2 + b 1 c 1 a 3 + a 3 b 3 c 3 − a 3 b 3 c 3

= a 3 c 3 + a 2 c 2 + a 1 c 1 b 1 − b 3 c 3 + b 2 c 2 + b 1 c 1 a 1   , a 1 c 1 + a 3 c 3 + a 2 c 2 b 2 − b 1 c 1 + b 3 c 3 + b 2 c 2 a 2     , a 2 c 2 + a 1 c 1 + a 3 c 3 b 3 − b 2 c 2 + b 1 c 1 + b 3 c 3 a 3

= a 3 c 3 + a 2 c 2 + a 1 c 1 b 1 , a 1 c 1 + a 3 c 3 + a 2 c 2 b 2 , a 2 c 2 + a 1 c 1 + a 3 c 3 b 3  − b 3 c 3 + b 2 c 2 + b 1 c 1 a 1 , b 1 c 1 + b 3 c 3 + b 2 c 2 a 2 , b 2 c 2 + b 1 c 1 + b 3 c 3 a 3

= a 3 c 3 + a 2 c 2 + a 1 c 1 b 1 , b 2 , b 3 − b 3 c 3 + b 2 c 2 + b 1 c 1 a 1 , a 2 , a 3

= a → · c → b → − b → · c → a →

すなわち

a → × b → × c → = a → · c → b → − b → · c → a →  ・・・・・・(1)

● a → × b → × c →

a → × b → × c → = a → · c → b → − a → · b → c →

a → × b → × c → = a 1 , a 2 , a 3 × b 1 , b 2 , b 3 × c 1 , c 2 , c 3

= a 1 , a 2 , a 3 × b 2 c 3 − b 3 c 2 , b 3 c 1 − b 1 c 3 , b 1 c 2 − b 2 c 1

= a 2 b 1 c 2 − b 2 c 1 − a 3 b 3 c 1 − b 1 c 3   , a 3 b 2 c 3 − b 3 c 2 − a 1 b 1 c 2 − b 2 c 1     , a 1 b 3 c 1 − b 1 c 3 − a 2 b 2 c 3 − b 3 c 2

= a 2 b 1 c 2 − a 2 b 2 c 1 − a 3 b 3 c 1 + a 3 b 1 c 3   , a 3 b 2 c 3 − a 3 b 3 c 2 − a 1 b 1 c 2 + a 1 b 2 c 1     , a 1 b 3 c 1 − a 1 b 1 c 3 − a 2 b 2 c 3 + a 2 b 3 c 2

= a 2 b 1 c 2 + a 3 b 1 c 3 − a 2 b 2 c 1 + a 3 b 3 c 1   , a 3 b 2 c 3 + a 1 b 2 c 1 − a 3 b 3 c 2 + a 1 b 1 c 2    , a 1 b 3 c 1 + a 2 b 3 c 2 − a 1 b 1 c 3 + a 2 b 2 c 3

= a 2 c 2 + a 3 c 3 b 1 − a 2 b 2 + a 3 b 3 c 1   , a 3 c 3 + a 1 c 1 b 2 − a 3 b 3 + a 1 b 1 c 2     , a 1 c 1 + a 2 c 2 b 3 − a 1 b 1 + a 2 b 2 c 3

= a 2 c 2 + a 3 c 3 b 1 − a 2 b 2 + a 3 b 3 c 1 + a 1 b 1 c 1 − a 1 b 1 c 1   , a 3 c 3 + a 1 c 1 b 2 − a 3 b 3 + a 1 b 1 c 2 + a 2 b 2 c 2 − a 2 b 2 c 2     , a 1 c 1 + a 2 c 2 b 3 − a 1 b 1 + a 2 b 2 c 3 + a 3 b 3 c 3 − a 3 b 3 c 3

= a 2 c 2 + a 3 c 3 + a 1 c 1 b 1 − a 2 b 2 + a 3 b 3 + a 1 b 1 c 1   , a 3 c 3 + a 1 c 1 + a 2 c 2 b 2 − a 3 b 3 + a 1 b 1 + a 2 b 2 c 2    , a 1 c 1 + a 2 c 2 + a 3 c 3 b 3 − a 1 b 1 + a 2 b 2 + a 3 b 3 c 3

= a 2 c 2 + a 3 c 3 + a 1 c 1 b 1 , a 3 c 3 + a 1 c 1 + a 2 c 2 b 2 , a 1 c 1 + a 2 c 2 + a 3 c 3 b 3  − a 2 b 2 + a 3 b 3 + a 1 b 1 c 1 , a 3 b 3 + a 1 b 1 + a 2 b 2 c 2 , a 1 b 1 + a 2 b 2 + a 3 b 3 c 3

= a 2 c 2 + a 3 c 3 + a 1 c 1 b 1 , b 2 , b 3 − a 2 b 2 + a 3 b 3 + a 1 b 1 c 1 , c 2 , c 3

= a → · c → b → − a → · b → c →

よって

a → × b → × c → = a → · c → b → − a → · b → c →  ・・・・・・(2)

(1),(2)より

a → × b → × c → ≠ a → × b → × c →

 

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最終更新日 2023年2月20日