演習問題

次の式のグラフを描け．

${\displaystyle y=2^x+1}$

次の式のグラフを描け．

${\displaystyle y=2^{x+2}-1}$

次の式のグラフを描け．

${\displaystyle y=2^{x+2}-1}$

次の式のグラフを描け．

${\displaystyle y=2^{x+1}+2}$

次の式のグラフを描け．

${\displaystyle y=2^{x+1}+2}$

次の式のグラフを描け．

${\displaystyle y=4^x}$

次の式のグラフを描け．

${\displaystyle y=4^x}$

次の式のグラフを描け．

${\displaystyle y=2^{2x+1}+1}$

次の式のグラフを描け．

${\displaystyle y=2^{2x+1}+1}$

次の式のグラフを描け．

${\displaystyle y=2^{2x+1}+1}$

次の式のグラフを描け．

${\displaystyle y=2^{3x+1}+2}$

次の式のグラフを描け．

${\displaystyle y=2^{3x+1}+2}$

関数 ${\displaystyle f(x)=A{e}^{-bx}}$ が次を満たすとき， $A$ ， $b$ を求めよ．

${\displaystyle f(0)=4}$ ， ${\displaystyle f(2)=1}$

関数 ${\displaystyle f(x)=A{e}^{-bx}}$ が次を満たすとき， $A$ ， $b$ を求めよ．

${\displaystyle f(0)=4}$ ， ${\displaystyle f(2)=1}$

${\displaystyle {\log }_{2}4}$

${\displaystyle {log}_{\frac{1}{2}}32}$

${\displaystyle {log}_{\frac{1}{2}}32}$

${\displaystyle {log}_{\frac{1}{2}}32}$

${\displaystyle {log}_{\frac{1}{2}}32}$

${\displaystyle {log}_{\frac{1}{2}}32}$

次の等式が成立することを示せ．

${\displaystyle {log}_{a}b=\frac{1}{{log}_{b}a}}$

次の式を簡単にせよ．

${\displaystyle {log}_{6}18+{log}_{6}12}$

次の式を簡単にせよ．

${\displaystyle {log}_{6}18+{log}_{6}12}$

次の式を簡単にせよ．

${\displaystyle {log}_{6}18+{log}_{6}12}$

次の式を簡単にせよ．

${\displaystyle {\text{log}}_{\text{2}}81·{\text{log}}_{\text{3}}2}$

次の式を簡単にせよ．

${\displaystyle {\text{log}}_{\text{2}}81·{\text{log}}_{\text{3}}2}$

次の式を簡単にせよ．

${\displaystyle {\text{log}}_{\text{2}}81·{\text{log}}_{\text{3}}2}$

次の式を簡単にせよ．

${\displaystyle {log}_9\sqrt[\text{4}]{\text{3}}+{log}_{\frac{1}{3}}9}$

次の式を簡単にせよ．

${\displaystyle {log}_9\sqrt[\text{4}]{\text{3}}+{log}_{\frac{1}{3}}9}$

次の式を簡単にせよ．

${\displaystyle {log}_9\sqrt[\text{4}]{\text{3}}+{log}_{\frac{1}{3}}9}$