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微分(1)の1．(2)の解答

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f( x )= x 2
f ′ ( x ) = lim Δx→0 ( Δx+x ) 2 − x 2 Δx = lim Δx→0 Δx( 2x+Δx ) Δx = lim Δx→0 2x+Δx = 3x
⇒次の問題の解答
⇒ヒント1
⇒解説１
⇒微分(1)のTOPへ戻る

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