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積分(2)の1．(6)の解答

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∫ 1 x 2 +9 dx
= ∫ 1 9 · 1 x 2 9 +1 dx = 1 9 ∫ 1 ( x 3 ) 2 +1 dx = 1 9 ·3 tan −1 x 3 +C = 1 3 tan −1 x 3 +C
⇒ヒント1
⇒解説1
⇒積分(2)のTOPへ戻る

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