”÷•ª‰‰ŽZŽq‚ÌŠî–{ŒöŽ®

(1)   ${\displaystyle f\left(D\right)e^{\alpha x}=f\left(\alpha \right)e^{\alpha x}}$ �@⇒�Ø–¾

(2)   ${\displaystyle f\left(D\right)\left[e^{\alpha x}y\right]}$${\displaystyle =e^{\alpha x}f\left(D+\alpha \right)y}$ ⇒�Ø–¾

 

 

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