k=1nkm‚ÌŒöŽ®

  • k=1 n k = n ( n+1 ) 2 @Ë“±o
  • k = 1 n k 2 = 1 2 + 2 2 + 3 2 + n 2 = n ( n + 1 ) ( 2 n + 1 ) 6 @Ë“±o
  • k=1 n k 3 = 1 3 + 2 3 + 3 3 ++ n 3 = { n ( n+1 ) 2 } 2 @Ë“±o
  • k = 1 n k 4 = 1 4 + 2 4 + 3 4 + + n 4 = 1 30 n ( n + 1 ) ( 2 n + 1 ) ( 3 n 2 + 3 n 1 ) @Ë“±o

 

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